2N3055 Power Transistor: Pinout, Equivalent, Datasheet ….2N3055 Datasheet, Pinout, Application Circuits Last Updated on Januby Swagatam 18 Comments The 2N3055 is a power bipolar transistor designed to handle high power loads in the range of 100 V, and 15 amps.2N3055 Datasheet, Pinout, Application Circuits - ….The transformer is used 2A min for the 1-2A load.
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You can use the Bridge Diode 2A-4A 200V to replace D1-D4. T1: 230V or 120V AC primary to 30V, 1A-2A secondary transformer Resistors (All 0.25 watt,5% metal/carbon film, Unless stated otherwise) When the output is connected with the low resistance load, the power transistor-Q2 will get very hot, so we always use a heat sink on it.ĬR: 2N3055 photo by STS Parts will you need
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This makes the 38V constant voltage and high power across resistor R3 and the (+) and (-) output terminals. The electrolytic capacitor-C2 is used for the smoothed Zener voltage. The 40V Zener Diode-ZD1 keeps the voltage constant across the base of BD139 NPN transistor-Q1 and Q2-2N3055 as the Darlington form. The capacitor C1, C3 acts as the storage capacitor or filters the noise and spikes off the AC. The full-wave rectifier bridge, D1 through D4 to rectifies the AC into pulsating DC, then filtered by C1. When 230VA or 120VAC (USA) is provided, step-down transformer-T1 changes the power line AC to about 30VAC. This regulated power supply included a transformer-T1, a bridge-D1…D4, and the 38V DC filtering voltage regulator circuits, which consists of C1, C2, R1, R2, R3, Q1, and Q2. We use the Simple Zener diode voltage regulator as main ideas, and two transistors to increase current to the load at 1A-2A. This circuit is one of the right choices. We have many ways to use it, but what is best for him. My friend is learning about CNC, he wants a 38V Regulated Power Supply for servo motor. So, for this reason, we should keep it cold with an effective heat sink. And it will result in enormous heating problems. The whole input voltage will be dropped across the power transistor. The VEC is 20V-5V = 15V So, the wattage is 15 watts. It needs to dissipate wattage is 7V x 1A = 7W. The voltage across the transistor (VCE)is 20V -12V = 7V. It needs to dissipate wattage is 5V x 1A = 5W. The voltage across the transistor (VCE) is 20V -15V = 5V. It is effectively a dropper resistor and must dissipate heat according to ohms law. The transistor of C is dropping the most voltage. At 1A the current.ĭo you know which transistor has the most heat loss? Or… It must dissipate or reduce it.ĭo you see an image? It is simple. The transistor-Q1 works look like a resistor.
#2N3055 TRANSISTOR REPLACEMENT SERIES#
In this series pass transistor regulator. Of course, energy will be expressed by heat. It should reduce the loss of energy in the circuit to a minimum. The transistor- 2N3055 can power load current up to 2A. The circuit will induct them into the transient noise. The power supply has a stray magnetic field.
![2n3055 transistor replacement 2n3055 transistor replacement](https://www.bristolwatch.com/ele/darlington/darlington1.jpg)
C1 is a smoothing capacitor at an input.Thus, it has a much more stabilized output. The advantage of this circuit, we can use a tiny current to Zener diode and base of a transistor.
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Because the voltage of Base-emitter less, transistor Q1 works less too. So it keeps the output voltage to be a constant level. But the base-emitter voltage rises up, transistor Q1 works more. In general, the output voltage is low down. In the circuit, the transistor has a proper gain and changing of VBE help it. Since it is a power supply that regulates a certain power output. This voltage is still suitable for many loads using the 12V supply such as receiver radios.